You can enter the line using namespace std;
for your convenience. Otherwise, you’ll have to explicitly add std::
every time you wish to use cout
, fixed
, showpoint
, setprecision(2)
and endl
#include <iostream>
#include <iomanip>
int main () {
double f =3.14159;
std::cout << std::setprecision(5) << f << '\n';
std::cout << std::setprecision(9) << f << '\n';
std::cout << std::fixed;
std::cout << std::setprecision(5) << f << '\n';
std::cout << std::setprecision(9) << f << '\n';
return 0;
}
std::setprecision. /*unspecified*/ setprecision (int n);. Set decimal precision. Sets the decimal precision to be used to format floating-point values on output
C++ setprecision not working
You could #include <limits>
, remove the step that gets the precision from input and change your code to:
std::cout << std::setprecision(std::numeric_limits<float>::max_digits10);
The answer above is absolutely correct. Here is a Turbo C++ version of it.
#include <iomanip.h>
#include <iostream.h>
void main()
{
double num1 = 3.12345678;
cout << setiosflags(fixed) << setiosflags(showpoint);
cout << setprecision(2);
cout << num1 << endl;
}
C++ setprecision without rounding
How to fixed number of digits in C++ without rounding
If you would like to truncate the value to two decimal places, you can multiply it by 100, truncate to integer, and then divide by 100, like this:
#include <iomanip.h>
#include <iostream.h>
void main()
{
c = a / b;
c = floor(100 * c) / 100;
cout<<"Result: "<<fixed<<setprecision(2)<<c<<endl;
return 0;
}
C++ round to two decimal places
Rounding Floating Point Number To two Decimal Places in C and C++. Difficulty Level : Medium. Round off a floatig point value to two places. Floating Point Operations & Associativity in C, C++
I know how to round off a number to only 2 decimal points? For example, 2.789 becomes 2.79
2.43 become 2.4
I want to round a floating point numbers after 2 decimal places.
Ex–
float x=3.1459;
float y;
I want ro round ‘x’ up tp 2 decimal places and store it in ‘y’ so that y=3.15.
To round a double up to 2 decimal places, you can use:
#include <iostream>
#include <cmath>
int main() {
double value = 0.123;
value = std::ceil(value * 100.0) / 100.0;
std::cout << value << std::endl; // prints 0.13
return 0;
}
To round up to n decimal places, you can use:
double round_up(double value, int decimal_places) {
const double multiplier = std::pow(10.0, decimal_places);
return std::ceil(value * multiplier) / multiplier;
}
This method won’t be particularly fast, if performance becomes an issue you may need another solution.
How to limit decimal places in c++
The following code will solve your problem (limit decimal places in c++).
#include <iostream> int main() { double d = 5.477225575051661134; float digit; double sc = 0.0001; digit = (int)(d/sc)*sc; std::cout << digit; return 0; }
double scale = 0.01; // i.e. round to nearest one-hundreth
value = (int)(value / scale) * scale;
or (rounding up/down as appropriate, per jheriko’s answer)
double scale = 0.01; // i.e. round to nearest one-hundreth
value = floor(value / scale + 0.5) * scale;
For the latter:
cout << setprecision(2) << value;
where the parameter to setprecision()
is the maximum number of digits to show after the decimal point.
C++ fixed
std::fixed – Fixed Floating-point notation : It write floating-point values in fixed-point notation. The fixed() method of stream manipulators in C++ is used to set the float field format flag for the specified str stream.
fixed() method of stream manipulators in C++ is used to set the floatfield format flag for the specified str stream. This flag sets the floatfield to fixed.
Showpoint c++
std::showpoint. ios_base& showpoint (ios_base& str);. Show decimal point. Sets the showpoint format flag for the str stream.
The showpoint() method of stream manipulators in C++ is used to set the showpoint format flag for the specified str stream.
C++ ios Library – Showpoint Function – It is used to sets the showpoint format flag for the str stream. When the showpoint format flag is set.
If the precision is 0 and showpoint
is not used, no decimal-point appears, else it does appear:
#include <iostream>
#include <iomanip>
int
main()
{
double pi = 2646693125139304345./842468587426513207.;
std::cout << std::fixed << std::setprecision(0);
std::cout << pi << '\n';
std::cout << std::showpoint;
std::cout << pi << '\n';
}
Should output:
3
3.